2009-09-04 16:34
http://jquery.org.cn/visual/cn/index.xml(jQuery 学习文档)
struts.xml
applicationContext.xml
http://www.springframework.org/schema/tx
UserAction.java(Action)
( 只有一个 userManager 的 set 方法没有 get 方法。写在 spring 注入是会同时
提供 get 和 set 方法,若使用 json 执行 action 后返回 json 数据,此时就会出
现上面的异常错误。解决办法是,去掉 get 方法。
package com.mybbs.action;
import com.mybbs.manager.UserManager;
import com.mybbs.vo.User;
import com.opensymphony.xwork2.ActionSupport;
public class UserAction extends ActionSupport {
UserManager userManager;
User user;
public String info;
public User getUsery() {
return usery;
}
public void setUsery(User usery) {
this.usery = usery;
}
public String check() throws Exception {
System.out.println(username);
User user1=userManager.check(user.getUsername());
ll){
}
info="恭喜你可以使用";
}else{
info="用户已经存在";
}
System.out.println(info);
return SUCCESS;
public void setUserManager(UserManager userManager) {
this.userManager = userManager;
}---
public User getUser() {
return user;
}
public void setUser(User user) {
this.user = user;
}
}
public void setInfo(String info) {
this.info = info;
public String getInfo() {
return info;
}
}
index.jsp
<%@ page language="java" pageEncoding="GBK"%>
<%
String path = request.getContextPath();
String basePath =
request.getScheme()+"://"+request.getServerName()+":"+request.getServ
erPort()+path+"/";
%>
My JSP 'register.jsp' starting page