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2007年湖南省张家界市中考数学真题及答案.doc

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2007 年湖南省张家界市中考数学真题及答案 注意事项: 1.答题前,考生务必将自己的姓名、准考证号写在答题卡和该试题卷的封面上,并将准考证号下面对应的 信息点用 2B 铅笔涂黑. 2.考生作答时,选择题和非选择题均须写在答题卡上,在草稿纸和本试题卷上答题无效.考生在答题卡上 按如下要求答题: (1)选择题部分请用 2B 铅笔把对应题目的答案标号所在方框涂黑,修改时用橡皮擦干净,不留痕迹. (2)非选择题部分(包括填空题和解答题)请按题号用 0.5 毫米黑色墨水签字笔书写,否则作答无效. (3)保持字体工整、笔迹清晰、卡面清洁、不折叠. 3.考试结束后,将本试题卷和答题卡一并交回. 4.本试题卷共 3 页.如缺页,考生须声明,否则后果自负. 考生注意:本学科试卷共三道大 25 小题,满分 120 分,考试时量 120 分钟. 一、选择题:(本题 8 小题,每小题 3 分,满分 24 分) 1.3 的相反数是( ) A.3 B. 3 C. 1 3 D. 3 2.下面是某几何体的三种视图,则该几何体是( ) 主视图 B.圆台 左视图 俯视图 A.圆柱 3.数轴上阴影部分表示的是某不等式组的解集,它的具体范围是( D.直棱柱 C.圆锥 A. x   2 B. 2   ≤ x 1 C. 2  ≤ ≤ x 1 D.  3  2  1 0 1 2 3 ) 1 x ≤ 4.一组数据共 4 个数,其众数为 6,中位数为 5,平均数为 4,则这组数据是( A.0 6 5.沿着虚线将矩形剪成两部分,既能拼成三角形又能拼成梯形的是( 5 ) C.1 D.4 B.1 5 6 6 6 6 4 3 6 6 ) 6 A. B. 6.下列事件中是必然事件的是( A.明天我市天气晴朗 C.抛一枚硬币,正面朝下 C. D. ) B.两个负数相乘,结果是正数 D.在同一个圆中,任画两个圆周角,度数相等 中, ACB  90  ,CD AB , DE BC , 7.如图在 ABC△ 那么与 ABC△ A.1 个 相似的三角形的个数有( ) B.4 个 C.3 个 D.2 个 A C D E B
8.观察一列有规律的数:4,8,16,32,…,它的第 2007 个数是( ) A. 20072 B. 20072 1 C. 20082 D. 20062 二、填空题(本题 8 小题,每小题 3 分,满分 24 分) A , 在函数 9.已知点 (3 5) k  x 10.在四边形 ABCD 中, AC  点,则四边形 EFGH 的周长为 y  上,则 k  . 4cm , 4.5cm BD  . ,E F G H , , , 分别是边 AB BC CD DA , , , 的中 H A D G C F E B 11.温家宝总理在今年政府工作报告中指出:今后 5 年国家财政新增加义务教育经费累计将达 218200000000 元,用科学记数法表示为 元. 12.分解因式 2 2  xy xy   x . 13.随着中国经济的高速发展,股市持续上涨,到 2007 年 5 月 28 日止,股市的开户人数已达到 1 亿人,同日对股民的市 场抽样调查如右图所示,据此估计当日对后市看涨的股民为 万人. 14.关于 x 的方程 2 3  x x   的一个根是 1 ,另一根是 0 k 看跌 13.10% 看平 20.69% 看涨 66.21% . 15.将 ABC△  绕点C 顺时针旋转得到 A B C △  ,已知   ACA  90 , BC  3 ,则点 B 旋转经过的路线 长是 . A 16.若 3 2k  有意义,则函数 y kx 1  的图象不经过第 象限. 三、解答题(本大题 9 小题,满分 72 分) 17.(本小题 6 分) 计算: 3 2   2 2   18 tan 45    (4sin 60  0  1)  | 2 3 2 |  . B A C B 18.(本小题 6 分) 如图所示方格纸中,每个方格都是边长为 1 的正方形, ABC△ 小正方形顶点)请按下列要求在答题卡上分别画 A B C  (1)把 ABC△ (2)将 ABC△ △ 向右平移 4 个单位得 A B C   ; 关于直线l 作轴反射得 A B C   △ △ .  的顶点 A B C, , 是方格纸中的三个格点(即 △  , A B C :  l A B C
19.(本小题 6 分) 河边有一条笔直的公路,公路两侧是平坦地带,一次活动课,老师要求测量河的宽度.一同学的测量结果 BCD 如图所示: CD 请你帮助计算河的宽度 AB (结果保留根号).  BDC 45 ,   30  ,  70 米. B A 45° D 30° C 20.(本小题 6 分) 如图,在四边形 ABCD 中, AB AD 中 BE 和 DE 是否相等?若相等,请写出证明过程;若不相等,请说明理由. , BC DC ,E 为 AC 上的一动点(不与 A 重合),在 E 移动过程 A E D B C 21.(本小题 9 分) 有两张背面相同的纸牌,其正面分别是正三角形和圆,将这两张纸牌背面朝上洗匀后摸出一张,放回洗匀 后,再摸出一张. (1)写出两次摸牌出现的所有可能的结果. (2)求两次摸出都是圆的概率. 22.(本小题 9 分) 张桑公路有一隧道,由 A 队单独施工,预计 200 天贯通.为了公路早日通车,由 A,B 两队同时施工,结果 120 天就贯通了.试问:如果由 B 队单独施工,需要多少天才能贯通?
23.(本小题 9 分) 当 a  2 1  时,求 a a   1 a  1 ( a 2 4  2 1)   1 2  1 a 的值. 24. (本小题 9 分) 如图,已知 AB 为圆O 的弦(非直径),E 为 AB 的中点,EO 的延长线交圆于点C ,CD AB∥ ,且交 AO 的延长线于点 D . :EO OC 1: 2 CD  ,求圆O 的半径. , 4  25. (本小题 12 分) A E O C B D 抛物线 y  2 ax  bx  交 x 轴于 A B, 两点,交 y 轴于点 C ,对称轴为直线 1x  ,已知: ( 1 0) A  , , c C , . (0 3) 2  c  ax (1)求抛物线  的解析式; bx 和 BOC△ y (2)求 AOC△ (3)在对称轴是否存在一个点 P ,使 PAC△ 明理由. 的面积的比; 的周长最小.若存在,请求出点 P 的坐标;若不存在,请说 y A O 1 x B C
张家界 2007 年初中毕业学业考试数学试卷 答案及评分标准 一、选择题 1.B 2.A 二、填空题 3.C 4.A 5.D 6.B 7.B 8.C 9. 15 10.8.5cm 11. 11 2.182 10 12. ( x y  1) 2 13.6621 万人 14. 2 15. 三、解答题 3 π 2 16.二 17.解:原式 2 3 2 1 1 (3 2 2)        ·························································4 分    2 3 2 1 1 3 2 2  ············································································· 5 分    0 ·············································································································· 6 分 18.(略)每个图形 3 分 19.解:在 Rt ABC△ 中, BCD  30  , tan 30  AB AC ,··································· 1 分  AC  AB tan 30  3 AB ,···············································································2 分 中, 在 Rt ABC△ 又 AC AD CD   BDC  45  , AD AB .··················································3 分 ,·····················································································4 分 AB AB   ,······················································································ 5 分 70  3  35 3 35  .······················································································· 6 分 AB  20.解:相等.·······························································································1 分 证明:在 ABC△ AB AD ABC  ,··········································································· 3 分 ,··················································· 2 分 (公共边) BC DC , AC AC 和 ADC△ (SSS) ADC ≌△ 中, △ BAE DAE    和 ABE△ 在 ADE△ AB AD , BAE    AE AE ,  DAE ≌△ ADE ABE △ , ,·······················································································4 分 中, (SAS) ···············································································5 分  BE DE .······························································································· 6 分 21.解:(1)正三角形和正三角形 正三角形和圆 圆和正三角形 圆和圆(写对一种情况 1 分)共计 4 分. (2)两张都是圆的概率的 1 4 .·········································································· 9 分
 1 22.解:设 B 队单独施工需要 x 天才能贯通,·······················································1 分 120 120  ,····························································································· 4 分 200 x 解方程得 300 x  ,························································································· 7 分 检验 300 是原方程的根,且符合题意.···························································8 分 答: B 队单独施工需要 300 天才能贯通.·····························································9 分 x  23.解:原式  a a a   1 (  1 2)( a  ( 1) a   2 2) (  2 a  1) ·························································3 分  a a a   1 (  1 2)( a  ( 1) a   2 2) (  a  1)( a  1) ···································································· 4 分  ( a  2)( a  .··························································································· 5 分 2) 当 a  2 1  时, 原式 ( 2 1 2)( 2 1 2)      ·········································································· 6 分  ( 2 3) ( 2 1)    ·························································································7 分  .···································································································9 分 2 2 1  24.解: E 是 AB 的中点, 90  OE AB ,即 AEO   DOE  AB CD∥ , AOE     AOE ∽△    DOC △ : AE DC OE OC 2 AE 2 OE :   OA OC 1 2  CD 又   AE OE  而 2 2  2 OA ,  ,······································································· 1 分  90  ,······································································ 2 分 OCD ,······················································································ 3 分 ,··················································································· 4 分  ,··········································································5 分 1: 2  .························································································ 6 分 ,··················································································· 7 分  OE 2   4 (2 OE 2 ) , OE  圆O 的半径 OA  2 OE  2 3 2 3 3 3 2   ,·······························································8 分 4 3 3 .····················································· 9 分 25.解:(1) A B , 两点关于 1x  对称, B 点坐标为 (3 0), ,···························· 1 分
根据题意得: ··········································································· 2 分 x  .································································ 3 分 3  0 9 3 a b c        0 a b c    3 c  2 c   , y 3 2 2    .  x b a , 解得 1  抛物线的解析式为 和 BOC△ | |  OA OC | (2) AOC△ 1 | S 2 | 1 OA  ,| 而| AOC  △ 的面积分别为 , S △ BOC  1 | 2 OB OC | |  | ,··············································· 4 分 OB  ,··················································································· 5 分 | 3  S △ AOC : S △ BOC |  OA OB |:| | 1:3  .································································ 6 分 (3)存在一个点 P .·······················································································7 分 C 点关于 1x  对称点坐标C 为 (2 3), ,··························································· 8 分 令直线 AC 的解析式为 y  kx b   3 2 k b         0 k b  ······························································································ 9 分  k   , 1 b   ,即 AC 的解析式为 1 y x   .··········································· 10 分 1 为 1x  时, y   ,·····················································································11 分 2  P 点坐标为 (1 2), .·················································································· 12 分
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