实验三:AES 加密算法构造
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通过上机操作,使学生对高级加密标准 AES 算法的执行过程、密钥编排方案和加密算法的实
现过程等有一个更加清晰地认识。通过本次实验,加深学生对分组密码的认识。
实验内容及要求
1 、 假 设 有 128 比 特 的 AES 密 钥 , 它 的 十 六 进 制 表 示 为 :
2B7E151628AED2A6ABF7158809CF4F3C,以此为种子密钥构造完整的密钥编排方案。
2、使用上述密钥,在10轮AES下计算下列明文(以十六进制表示)的加密结果:
3243F6A8885A308D313198A2E0370734。
实验结果(可续页)(包括实验代码、实验结果)
一、实验代码:
#include
#include
#include
using namespace std;
typedef bitset<8> byte;
typedef bitset<32> word;
const int Nr = 10;
const int Nk = 4;
// AES-128 需要 10 轮加密
// Nk 表示输入密钥的 word 个数
byte S_Box[16][16] = {
{0x63, 0x7C, 0x77, 0x7B, 0xF2, 0x6B, 0x6F, 0xC5, 0x30, 0x01, 0x67, 0x2B, 0xFE, 0xD7,
0xAB, 0x76},
{0xCA, 0x82, 0xC9, 0x7D, 0xFA, 0x59, 0x47, 0xF0, 0xAD, 0xD4, 0xA2, 0xAF, 0x9C, 0xA4,
0x72, 0xC0},
{0xB7, 0xFD, 0x93, 0x26, 0x36, 0x3F, 0xF7, 0xCC, 0x34, 0xA5, 0xE5, 0xF1, 0x71, 0xD8, 0x31,
0x15},
{0x04, 0xC7, 0x23, 0xC3, 0x18, 0x96, 0x05, 0x9A, 0x07, 0x12, 0x80, 0xE2, 0xEB, 0x27, 0xB2,
0x75},
{0x09, 0x83, 0x2C, 0x1A, 0x1B, 0x6E, 0x5A, 0xA0, 0x52, 0x3B, 0xD6, 0xB3, 0x29, 0xE3,
0x2F, 0x84},
{0x53, 0xD1, 0x00, 0xED, 0x20, 0xFC, 0xB1, 0x5B, 0x6A, 0xCB, 0xBE, 0x39, 0x4A, 0x4C,
0x58, 0xCF},
{0xD0, 0xEF, 0xAA, 0xFB, 0x43, 0x4D, 0x33, 0x85, 0x45, 0xF9, 0x02, 0x7F, 0x50, 0x3C, 0x9F,
0xA8},
{0x51, 0xA3, 0x40, 0x8F, 0x92, 0x9D, 0x38, 0xF5, 0xBC, 0xB6, 0xDA, 0x21, 0x10, 0xFF, 0xF3,
0xD2},
{0xCD, 0x0C, 0x13, 0xEC, 0x5F, 0x97, 0x44, 0x17, 0xC4, 0xA7, 0x7E, 0x3D, 0x64, 0x5D,
0x19, 0x73},
{0x60, 0x81, 0x4F, 0xDC, 0x22, 0x2A, 0x90, 0x88, 0x46, 0xEE, 0xB8, 0x14, 0xDE, 0x5E, 0x0B,
0xDB},
{0xE0, 0x32, 0x3A, 0x0A, 0x49, 0x06, 0x24, 0x5C, 0xC2, 0xD3, 0xAC, 0x62, 0x91, 0x95, 0xE4,
0x79},
{0xE7, 0xC8, 0x37, 0x6D, 0x8D, 0xD5, 0x4E, 0xA9, 0x6C, 0x56, 0xF4, 0xEA, 0x65, 0x7A,
0xAE, 0x08},
{0xBA, 0x78, 0x25, 0x2E, 0x1C, 0xA6, 0xB4, 0xC6, 0xE8, 0xDD, 0x74, 0x1F, 0x4B, 0xBD,
0x8B, 0x8A},
{0x70, 0x3E, 0xB5, 0x66, 0x48, 0x03, 0xF6, 0x0E, 0x61, 0x35, 0x57, 0xB9, 0x86, 0xC1, 0x1D,
0x9E},
{0xE1, 0xF8, 0x98, 0x11, 0x69, 0xD9, 0x8E, 0x94, 0x9B, 0x1E, 0x87, 0xE9, 0xCE, 0x55, 0x28,
0xDF},
{0x8C, 0xA1, 0x89, 0x0D, 0xBF, 0xE6, 0x42, 0x68, 0x41, 0x99, 0x2D, 0x0F, 0xB0, 0x54,
0xBB, 0x16}
};
byte Inv_S_Box[16][16] = {
{0x52, 0x09, 0x6A, 0xD5, 0x30, 0x36, 0xA5, 0x38, 0xBF, 0x40, 0xA3, 0x9E, 0x81, 0xF3, 0xD7,
0xFB},
{0x7C, 0xE3, 0x39, 0x82, 0x9B, 0x2F, 0xFF, 0x87, 0x34, 0x8E, 0x43, 0x44, 0xC4, 0xDE, 0xE9,
0xCB},
{0x54, 0x7B, 0x94, 0x32, 0xA6, 0xC2, 0x23, 0x3D, 0xEE, 0x4C, 0x95, 0x0B, 0x42, 0xFA,
0xC3, 0x4E},
{0x08, 0x2E, 0xA1, 0x66, 0x28, 0xD9, 0x24, 0xB2, 0x76, 0x5B, 0xA2, 0x49, 0x6D, 0x8B,
0xD1, 0x25},
{0x72, 0xF8, 0xF6, 0x64, 0x86, 0x68, 0x98, 0x16, 0xD4, 0xA4, 0x5C, 0xCC, 0x5D, 0x65, 0xB6,
0x92},
{0x6C, 0x70, 0x48, 0x50, 0xFD, 0xED, 0xB9, 0xDA, 0x5E, 0x15, 0x46, 0x57, 0xA7, 0x8D,
0x9D, 0x84},
{0x90, 0xD8, 0xAB, 0x00, 0x8C, 0xBC, 0xD3, 0x0A, 0xF7, 0xE4, 0x58, 0x05, 0xB8, 0xB3,
0x45, 0x06},
{0xD0, 0x2C, 0x1E, 0x8F, 0xCA, 0x3F, 0x0F, 0x02, 0xC1, 0xAF, 0xBD, 0x03, 0x01, 0x13,
0x8A, 0x6B},
{0x3A, 0x91, 0x11, 0x41, 0x4F, 0x67, 0xDC, 0xEA, 0x97, 0xF2, 0xCF, 0xCE, 0xF0, 0xB4,
0xE6, 0x73},
{0x96, 0xAC, 0x74, 0x22, 0xE7, 0xAD, 0x35, 0x85, 0xE2, 0xF9, 0x37, 0xE8, 0x1C, 0x75, 0xDF,
0x6E},
{0x47, 0xF1, 0x1A, 0x71, 0x1D, 0x29, 0xC5, 0x89, 0x6F, 0xB7, 0x62, 0x0E, 0xAA, 0x18,
0xBE, 0x1B},
{0xFC, 0x56, 0x3E, 0x4B, 0xC6, 0xD2, 0x79, 0x20, 0x9A, 0xDB, 0xC0, 0xFE, 0x78, 0xCD,
0x5A, 0xF4},
{0x1F, 0xDD, 0xA8, 0x33, 0x88, 0x07, 0xC7, 0x31, 0xB1, 0x12, 0x10, 0x59, 0x27, 0x80, 0xEC,
0x5F},
{0x60, 0x51, 0x7F, 0xA9, 0x19, 0xB5, 0x4A, 0x0D, 0x2D, 0xE5, 0x7A, 0x9F, 0x93, 0xC9,
0x9C, 0xEF},
{0xA0, 0xE0, 0x3B, 0x4D, 0xAE, 0x2A, 0xF5, 0xB0, 0xC8, 0xEB, 0xBB, 0x3C, 0x83, 0x53,
0x99, 0x61},
{0x17, 0x2B, 0x04, 0x7E, 0xBA, 0x77, 0xD6, 0x26, 0xE1, 0x69, 0x14, 0x63, 0x55, 0x21, 0x0C,
0x7D}
};
// 轮常数,密钥扩展中用到。(AES-128 只需要 10 轮)
word Rcon[10] = {0x01000000, 0x02000000, 0x04000000, 0x08000000, 0x10000000,
0x20000000, 0x40000000, 0x80000000, 0x1b000000, 0x36000000};
/************下面是加密的变换函数************/
//S 盒变换 - 前 4 位为行号,后 4 位为列号
void SubBytes(byte mtx[4*4])
{
for(int i=0; i<16; ++i)
{
int row = mtx[i][7]*8 + mtx[i][6]*4 + mtx[i][5]*2 + mtx[i][4];
int col = mtx[i][3]*8 + mtx[i][2]*4 + mtx[i][1]*2 + mtx[i][0];
mtx[i] = S_Box[row][col];
}
}
//行变换 - 按字节循环移位
void ShiftRows(byte mtx[4*4])
{
// 第二行循环左移一位
byte temp = mtx[4];
for(int i=0; i<3; ++i)
mtx[i+4] = mtx[i+5];
mtx[7] = temp;
// 第三行循环左移两位
for(int i=0; i<2; ++i)
{
temp = mtx[i+8];
mtx[i+8] = mtx[i+10];
mtx[i+10] = temp;
}
// 第四行循环左移三位
temp = mtx[15];
for(int i=3; i>0; --i)
mtx[i+12] = mtx[i+11];
mtx[12] = temp;
}
//有限域上的乘法 GF(2^8)
byte GFMul(byte a, byte b) {
byte p = 0;
byte hi_bit_set;
for (int counter = 0; counter < 8; counter++) {
if ((b & byte(1)) != 0) {
p ^= a;
}
hi_bit_set = (byte) (a & byte(0x80));
a <<= 1;
if (hi_bit_set != 0) {
a ^= 0x1b; /* x^8 + x^4 + x^3 + x + 1 */
}
b >>= 1;
}
return p;
}
//列变换
void MixColumns(byte mtx[4*4])
{
byte arr[4];
for(int i=0; i<4; ++i)
{
for(int j=0; j<4; ++j)
arr[j] = mtx[i+j*4];
mtx[i] = GFMul(0x02, arr[0]) ^ GFMul(0x03, arr[1]) ^ arr[2] ^ arr[3];
mtx[i+4] = arr[0] ^ GFMul(0x02, arr[1]) ^ GFMul(0x03, arr[2]) ^ arr[3];
mtx[i+8] = arr[0] ^ arr[1] ^ GFMul(0x02, arr[2]) ^ GFMul(0x03, arr[3]);
mtx[i+12] = GFMul(0x03, arr[0]) ^ arr[1] ^ arr[2] ^ GFMul(0x02, arr[3]);
}
}
// 轮密钥加变换 - 将每一列与扩展密钥进行异或
void AddRoundKey(byte mtx[4*4], word k[4])
{
for(int i=0; i<4; ++i)
{
word k1 = k[i] >> 24;
word k2 = (k[i] << 8) >> 24;
word k3 = (k[i] << 16) >> 24;
word k4 = (k[i] << 24) >> 24;
mtx[i] = mtx[i] ^ byte(k1.to_ulong());
mtx[i+4] = mtx[i+4] ^ byte(k2.to_ulong());
mtx[i+8] = mtx[i+8] ^ byte(k3.to_ulong());
mtx[i+12] = mtx[i+12] ^ byte(k4.to_ulong());
}
}
/************下面是密钥扩展部分************/
//将 4 个 byte 转换为一个 word.
word Word(byte& k1, byte& k2, byte& k3, byte& k4)
{
// K1
// K2
word result(0x00000000);
word temp;
temp = k1.to_ulong();
temp <<= 24;
result |= temp;
temp = k2.to_ulong();
temp <<= 16;
result |= temp;
temp = k3.to_ulong();
temp <<= 8;
result |= temp;
temp = k4.to_ulong();
result |= temp;
return result;
// K3
// K4
}
//按字节 循环左移一位
//即把[a0, a1, a2, a3]变成[a1, a2, a3, a0]
word RotWord(word rw)
{
word high = rw << 8;
word low = rw >> 24;
return high | low;
}
//对输入 word 中的每一个字节进行 S-盒变换
word SubWord(word sw)
{
word temp;
for(int i=0; i<32; i+=8)
{
int row = sw[i+7]*8 + sw[i+6]*4 + sw[i+5]*2 + sw[i+4];
int col = sw[i+3]*8 + sw[i+2]*4 + sw[i+1]*2 + sw[i];
byte val = S_Box[row][col];
for(int j=0; j<8; ++j)
temp[i+j] = val[j];
}
return temp;
}
//密钥扩展函数 - 对 128 位密钥进行扩展得到 w[4*(Nr+1)]
void KeyExpansion(byte key[4*Nk], word w[4*(Nr+1)])
{
word temp;
int i = 0;
// w[]的前 4 个就是输入的 key
while(i < Nk)
{
w[i] = Word(key[4*i], key[4*i+1], key[4*i+2], key[4*i+3]);
++i;
}
i = Nk;
while(i < 4*(Nr+1))
{
temp = w[i-1]; // 记录前一个 word
if(i % Nk == 0)
w[i] = w[i-Nk] ^ SubWord(RotWord(temp)) ^ Rcon[i/Nk-1];
w[i] = w[i-Nk] ^ temp;
else
++i;
}
}
/************下面是加密和解密函数************/
//加密
void encrypt(byte in[4*4], word w[4*(Nr+1)])
{
word key[4];
for(int i=0; i<4; ++i)
key[i] = w[i];
AddRoundKey(in, key);
for(int round=1; round
word w[4*(Nr+1)];
KeyExpansion(key, w);
// 输出待加密的明文
cout << endl << "待加密的明文:"<