实验一：编程练习 1) STACK SEGMENT STACK DW 64 DUP (?) ENDS SEGMENT ORG 0500H ；起始地址 DB 25H, 30H, 32H, 34H, 65H DB 5 DUP (?) ENDS SEGMENT ASSUME DS: DATA, CS: STACK DATA DATA1 DATA2 DATA CODE CODE START: MOV AX, DATA MOV DS, AX MOV AH, 0FFH； MOV CX, 05H；计数，五个数 LEA SI, DATA1 LEA DI, DATA2 NEXT: MOV AL, [SI] CMP AL, 3AH；比较 JNC FF1；CF=0 转移 CMP AL, 30H JC FF1；CF=1 转移 SUB AL, 30H MOV [DI], AL INC SI INC DI LOOP NEXT；CX≠0 则循环 JMP DONE MOV [DI], AH；把 FFH 存入 JMP BACK BACK: FF1: DONE: MOV AH, 4CH CODE INT 21H；程序退出 ENDS END START 2) STACK SEGMENT STACK DW 64 DUP (?) STACK ENDS DATA SEGMENT ORG 0500H DW 00AAH ORG 0510H DB 5 DUP (?)；0510H-0514H ENDS SEGMENT ASSUME DS: DATA, CS: DATA1 DATA2 DATA CODE CODE START: MOV AX, DATA MOV DS, AX MOV SI, OFFSET DATA1 MOV DI, OFFSET DATA2 MOV CX, 05H;计数，五位 MOV AX, [SI] XOR DX, DX；清空 DX MOV BX, 0AH DIV BX;DL,AX/BX 的余数？ ADD DL, 30H；变为 ASCII MOV [DI], DL INC DI LOOP DONE；CX≠0 则循环 MOV AH, 4CH INT 21H ENDS END START DONE: CODE 实验二：编程练习 2) STACK A: SEGMENT STACK DW 64 DUP (?) ENDS SEGMENT ORG 0500H DB 10H, 20H, 30H, 40H, 50H, ORG 0510H DB ? SEGMENT ASSUME DS: DATA, CS: CODE STACK DATA DATA1 60H DATA2 CODE MOV AH, 4CH INT 21H ENDS END START CODE 2)OPTIONAL 可选（不太懂） START: MOV AX, DATA MOV DS, AX MOV SI, OFFSET DATA1 MOV DI, OFFSET DATA2 MOV CX,0006H MOV AX,0000H MOV BL, [SI] INC SI ADD AL, BL ADC AH,00H；带进位的加法 LOOP A MOV CL,06H DIV CL MOV AH,00H MOV BL,0AH DIV BL MOV BH, AH MOV BL,10H MUL BL ADD AL, BH MOV [DI], AL MOV AH,4CH INT 21H ENDS END START CODE START: MOV AX, DATA A1: MOV DS, AX MOV SI, OFFSET DATA1 MOV DI, OFFSET DATA2 XOR DX, DX；清空 MOV CX, 6；计数 MOV AL, [SI] CBW；AL 扩展为 16 位 AX ADD DX, AX INC SI LOOP A1 MOV AX, DX MOV BL, 06H DIV BL MOV BL, 0AH；？？ DIV BL；详细见后面 MOV [DI], AX 3) STACK SEGMENT STACK DW 64 DUP (?) STACK ENDS DATA SEGMENT ORG 0500H DB 10H, 15H, 0FH ORG 0510H DB 3 DUP (?) ENDS SEGMENT ASSUME DS: DATA, CS: DATA1 DATA2 DATA CODE CODE START: MOV AX, DATA MOV DS, AX MOV SI, OFFSET DATA1 MOV DI, OFFSET DATA2 MOV AL, [SI] 

MOV BL, [SI+1] ADD AL, BL MOV BL, [SI+2] ADD AL, BL MOV CL,02H SALAL, CL；算术左移 2 位 MOV AH,00H MOV CX,03H XOR DX, DX；清空 DX MOV BX, 0AH DIV BX；十六进制转 BCD MOV [DI], DL INC DI LOOP DONE MOV AH, 4CH INT 21H ENDS DONE: CODE END START 实验三：编程练习 1) STACK STACK DATA DATA SEGMENT STACK DW 64 DUP (?) ENDS SEGMENT SEGMENT ORG 0500H DB 09H 数 据 个 数 ,12H, 80H, DATA1 78H, 0C8H, 00H, 00H, 0FEH, 99H, 34H DATA2 DATA CODE ORG 0510H DB 3 DUP (?) ENDS SEGMENT ASSUME DS: DATA, CS: CODE START: MOV AX, DATA MOV DS, AX MOV SI, OFFSET DATA1 MOV DI, OFFSET DATA2 MOV CL, [SI]；计数数据次数 MOV CH,00H MOV BH,00H MOV BL,00H MOV DL,00H INC SI MOV AL, [SI] CMP AL, 0 JLE A2 INC BH；正数加一 JMP OVER A2: A1: A1: A2: A3: OVER: CODE CMP AL, 0 JL A3 INC BL；零加一 JMP OVER INC DL；负数加一 INC SI；判断次数 LOOP A1 MOV [DI], BH；正数 MOV [DI+1], DL；负数 MOV [DI+2], BL；零 MOV AH,4CH INT 21H ENDS END START 2) STACK SEGMENT STACK DW 64 DUP (?) STACK ENDS DATA SEGMENT ORG 0200H DB 3 DUP (?) ORG 0204H DW ? ENDS SEGMENT ASSUME DS: DATA, CS: DATA1 DATA2 DATA CODE CODE START: MOV AX, DATA MOV DS, AX LEA SI, DATA1 LEA DI, DATA2 MOV AL, [SI] MOV AH, [SI+1] MOV BL, [SI+2]；将三数移到 CMPAL, AH JZ A1 CMPAL, BL;详细看后面 JZ A2 MOV [DI], SI JMPA4 INC SI MOV [DI], SI JMPA4 CMPAL, BL JZ A3 ADD SI, 2 MOV [DI], SI JMPA4 A3: A4: CODE MOV [DI], 0FFFFH；相同 MOV AH, 4CH INT 21H ENDS END START 实验四：编程练习 1) STACK SEGMENT STACK DW 64 DUP (?) ENDS SEGMENT STR1 DB 0AH, 0DH, 'Input STACK DATA two numbers A & B: $' ORG 0204H DB 3 DUP (?) ENDS SEGMENT ASSUME DS: DATA, CS: DATA1 DATA CODE CODE START: MOV AX, DATA A: MOV DS, AX MOV DX, OFFSET STR1 MOV AH, 09H；显示字符串 INT 21H MOV AH, 01H 输入单字符 INT 21H CMP AL, 0DH JZ OVER SUB AL, 30H MOV BL, AL MOV AH, 01H；输入单字符 INT 21H CMP AL, 0DH； “回车(0AH)”和“换行(0DH)” JZ OVER MOV AH, 00H SUB AL,30H ADD AL, BL AAA；将 AL 的和调整到 BCD 格式 ADD AH, 30H MOV DL, AH MOV BH, AL MOV AH, 02H；显示单 ASCII INT 21H ADD BH, 30H MOV DL, BH MOV AH, 02H 显示单 ASCII INT 21H JMP A 

JMP OVER A3: ADD DX,0CH OVER: MOV AH,09H INT 21H JMPA1 MOV AH,4CH INT 21H ENDS END START EX: CODE DIV src：AX 除以 src 中的值 商放 AL 余 数放 AH（8 位） DIV src：(DX,AX)除以 src 中的值 商放 AX 余数放 DX（16 位） CMP AX,BX 的逻辑含义是比较 AX,BX 中的值。如果执行后： ZF=1 则 AX=BX ZF=0 则 AX！=BX SF=1 则 AX=BX SF=0 并 ZF=0 则 AX>BX SF=1 或 ZF=1 则 AX<=BX OVER: MOV AH, 4CH CODE INT 21H ENDS END START 2)判断两个数大小，输出 A>B STACK SEGMENT STACK DW 64 DUP (?) STACK ENDS DATA SEGMENT STR1 DB 0AH, 0DH, 'Input data A:$', 0AH, 0DH, 'Input data B: $' STR2 DB 0AH, 0DH, 'A>B$', 0AH, 0DH, 'A=B$', 0AH, 0DH, 'A