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Principle of Econometrics_4th edition Answer.pdf

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Answers to Selected Exercises Chaps 1-7
Cover
Contents
Probability Primer Exercise Answers 18jan11
Chapter 2 Exercise Answers 15feb11
Chapter 3 Exercise Answers 16feb11
Chapter 4 Exercise Answers 16Feb2011
Chapter 5 Exercise Answers 16Feb2011
Chapter 6 Exercises Answers 16Feb2011
Chapter 7 Exercise Answers 17Feb2011
Chapter 8 Exercise Answers 29Aug2011
Chapter 9 Exercise Answers 29Aug2011
Chapter 10 Exercise Answers 29Aug11
Chapter 11 Exercise Answers 29Aug11
Chapter 15 Exercisse Answers 29Aug2011
Chapter 16 Exercise Answers 29Aug11
Appendix A Exercise Answers 29Aug11
Appendix B Exercise Answers 29Aug11
Appendix C Exercise Answers 29Aug11
Answers to Selected Exercises For Principles of Econometrics, Fourth Edition R. CARTER HILL Louisiana State University WILLIAM E. GRIFFITHS University of Melbourne GUAY C. LIM University of Melbourne JOHN WILEY & SONS, INC New York / Chichester / Weinheim / Brisbane / Singapore / Toronto
CONTENTS Answers for Selected Exercises in: Probability Primer Chapter 2 Chapter 3 Chapter 4 Chapter 5 Chapter 6 Chapter 7 Chapter 8 Chapter 9 Chapter 10 Chapter 11 Chapter 15 Chapter 16 Appendix A Mathematical Tools Appendix B Appendix C The Simple Linear Regression Model Interval Estimation and Hypothesis Testing Prediction, Goodness of Fit and Modeling Issues The Multiple Regression Model Further Inference in the Multiple Regression Model Using Indicator Variables Heteroskedasticity Regression with Time Series Data: Stationary Variables Random Regressors and Moment Based Estimation Simultaneous Equations Models Panel Data Models Qualitative and Limited Dependent Variable Models Probability Concepts Review of Statistical Inference 1 3 12 16 22 29 36 44 51 58 60 64 66 69 72 76 29 August, 2011
PROBABILITY PRIMER Exercise Answers EXERCISE P.1 (a) X is a random variable because attendance is not known prior to the outdoor concert. (b) (c) (d) 1100 3500 6,000,000 EXERCISE P.3 0.0478 EXERCISE P.5 (a) 0.5. (b) 0.25 EXERCISE P.7 (a) f c ( ) 0.15 0.40 0.45 (b) (c) (d) 1.3 0.51 f (0,0) 0.05   f C (0) f B (0) 0.15 0.15 0.0225    1
Probability Primer, Exercise Answers, Principles of Econometrics, 4e 2 (e) A 5000 6000 7000 f a ( ) 0.15 0.50 0.35 (f) 1.0 EXERCISE P.11 (a) (b) (c) (d) (e) 0.0289 0.3176 0.8658 0.444 1.319 EXERCISE P.13 (a) (b) (c) 0.1056 0.0062 (a) 0.1587 (b) 0.1265 EXERCISE P.15 (a) (b) (c) (d) (e) (f) 9 1.5 0 109 −66 −0.6055  EXERCISE P.17 x (a) 2 (b) (c) (d) (e) (f) a b x 4 ( 1 14 34 f (4) f (0, 36 (5)  f (1,  y ) f    x 3  x 4 ) f y ) (6) f  (2, y )
CHAPTER 2 Exercise Answers EXERCISE 2.3 (a) The line drawn for part (a) will depend on each student’s subjective choice about the position of the line. For this reason, it has been omitted. 1.514286 b   2 b  1 10.8 (b) Figure xr2.3 Observations and fitted line 0 1 8 6 4 2 1 2 3 x 4 y Fitted values 5 6 y  x  ˆ y  5.5 3.5 5.5 (c) 3
Chapter 2, Exercise Answers Principles of Econometrics, 4e 4 Exercise 2.3 (Continued) (d) ˆie 0.714286 0.228571 −1.257143 0.257143 −1.228571 1.285714 (e) ie  ˆ 0. ix e  ˆ i 0 240 b   1 is an estimate of the number of sodas sold when the The intercept estimate temperature is 0 degrees Fahrenheit. Clearly, it is impossible to sell 240 sodas and so this estimate should not be accepted as a sensible one. b  is an estimate of the increase in sodas sold when temperature The slope estimate 2 increases by 1 Fahrenheit degree. One would expect the number of sodas sold to increase as temperature increases. ˆ y   240 8 80    400 She predicts no sodas will be sold below 30F. A graph of the estimated regression line: Figure xr2.6 Regression line 0 0 6 0 0 4 0 0 2 y 0 0 0 2 - 0 20 40 x 60 80 100 EXERCISE 2.6 (a) 8 (b) (c) (d)
Chapter 2, Exercise Answers Principles of Econometrics, 4e 5 EXERCISE 2.9 (a) Figure xr2.9a Occupancy Rates 100 90 80 70 60 50 40 30 0 2 4 6 8 10 12 14 16 18 20 22 24 26 month, 1=march 2003,.., 25=march 2005 percentage motel occupancy percentage competitors occupancy The repair period comprises those months between the two vertical lines. The graphical evidence suggests that the damaged motel had the higher occupancy rate before and after the repair period. During the repair period, the damaged motel and the competitors had similar occupancy rates. A plot of MOTEL_PCT against COMP_PCT yields: Figure xr2.9b Observations on occupancy (b) 100 90 80 70 60 50 40 y c n a p u c c o l e t o m e g a t n e c r e p 40 50 60 70 80 percentage competitors occupancy There appears to be a positive relationship the two variables. Such a relationship may exist as both the damaged motel and the competitor(s) face the same demand for motel rooms.
Chapter 2, Exercise Answers Principles of Econometrics, 4e 6 Exercise 2.9 (continued)   21.40 0.8646 (c) _ MOTEL PCT The competitors’ occupancy rates are positively related to motel occupancy rates, as expected. The regression indicates that for a one percentage point increase in competitor occupancy rate, the damaged motel’s occupancy rate is expected to increase by 0.8646 percentage points. COMP PCT  _ . (d) l s a u d s e r i 30 20 10 0 -10 -20 -30 Repair period 0 4 8 12 16 20 24 28 month, 1=march 2003,.., 25=march 2005 Figure xr2.9(d) Plot of residuals against time The residuals during the occupancy period are those between the two vertical lines. All except one are negative, indicating that the model has over-predicted the motel’s occupancy rate during the repair period. (e) We would expect the slope coefficient of a linear regression of MOTEL_PCT on RELPRICE to be negative, as the higher the relative price of the damaged motel’s rooms, the lower the demand will be for those rooms, holding other factors constant. _ MOTEL PCT 166.66 122.12 RELPRICE    (f) The estimated regression is: _ MOTEL PCT In the non-repair period, the damaged motel had an estimated occupancy rate of 79.35%. During the repair period, the estimated occupancy rate was 79.35−13.24 = 66.11%. Thus, it appears the motel did suffer a loss of occupancy and profits during the repair period. 79.3500 13.2357 REPAIR    (g) From the earlier regression, we have MOTEL 0 MOTEL 1 b  1 79.35% b 1 b 2    79.35 13.24 66.11%  
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