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CMOS集成电路设计(拉扎维)答案.pdf

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    Chapter 1 Homework Solutions
    Chapter 2 Homework Solutions
    Chapter 3 Homework Solutions
    Chapter 4 Homework Solutions
    Chapter 5 Homework Solutions
    Chapter 6 Homework Solutions
    Chapter 7 Homework Solutions
    Chapter 8 Homework Solutions
    Chapter 9 Homework Solutions
    Chapter 10 Homework Solutions
    CMOS Analog Circuit Design (2nd Ed.) Homework Solutions : 9/20/2002 1 Chapter 1 Homework Solutions 1.1-1 Using Eq. (1) of Sec 1.1, give the base-10 value for the 5-bit binary number 11010 (b4 b3 b2 b1 b0 ordering). From Eq. (1) of Sec 1.1 we have bN-1 2-1 + b N-2 2-2 + bN-3 2-3 + ...+ b0 2-N =∑ bN-i2-i N i=1 0 1 1 1 × 2-1 + 1× 2-2 + 0 × 2-3 + 1 × 2-4 + 0 × 2-5 = 4 + 2 + 8 + 1 16 + 0 32 = 16 + 8 + 0 + 2 + 0 32 = 26 32 = 13 16 1.1-2 Process the sinusoid in Fig. P1.2 through an analog sample and hold. The sample points are given at each integer value of t/T. 15 14 13 12 11 e d 10 u t i 9 l p m 8A 7 6 5 4 3 2 1 0 1 2 3 4 5 6 7 8 9 10 11 Sample times t __ T Figure P1.1-2 1.1-3 Digitize the sinusoid given in Fig. P1.2 according to Eq. (1) in Sec. 1.1 using a four-bit digitizer.
    CMOS Analog Circuit Design (2nd Ed.) Homework Solutions : 9/20/2002 2 1111 1101 1110 1100 1000 1010 0110 15 14 13 12 11 e d 10 u t i 9 l p m 8A 7 6 5 4 3 2 1 1000 0101 0011 0010 0010 0 1 2 3 4 5 6 7 8 9 10 11 Sample times t __ T Figure P1.1-3 The figure illustrates the digitized result. At several places in the waveform, the digitized value must resolve a sampled value that lies equally between two digital values. The resulting digitized value could be either of the two values as illustrated in the list below. Sample Time 0 1 2 3 4 5 6 7 8 9 10 11 4-bit Output 1000 1100 1110 1111 or 1110 1101 1010 0110 0011 0010 or 0001 0010 0101 1000 1.1-4 Use the nodal equation method to find vout/vin of Fig. P1.4.
    CMOS Analog Circuit Design (2nd Ed.) Homework Solutions : 9/20/2002 3 A B R1 R2 vin R3 v1 gmv1 R4 vout Figure P1.1-4 Node A: 0 = G1(v1-vin) + G3(v1) + G2(v1 - vout) v1(G1 + G2 + G3) - G2(vout) = G1(vin) Node B: 0 = G2(vout-v1) + gm1(v1) + G4( vout) v1(gm1 - G2) + vout (G2 + G4) = 0 G1+G2 +G3   gm1 - G2  G1+G2 +G3   gm1 - G2     G1vin 0 - G2 G2 + G4    vout = vout vin = G1 (G2 - gm1) G1 G2 + G1 G4 + G2 G4 + G3 G2 + G3 G4 + G2 gm1 1.1-5 Use the mesh equation method to find vout/vin of Fig. P1.4. R1 R2 vin ia R3 v1 gmv1 ib R4 vout ic Figure P1.1-5 0 = -vin + R1(ia + ib + ic) + R3(ia)
    CMOS Analog Circuit Design (2nd Ed.) Homework Solutions : 9/20/2002 4 0 = -vin + R1(ia + ib + ic) + R2(ib + ic) + vout vout R4 ic = ib = gm v1 = gm ia R3   0 = -vin + R1 ia + gm ia R3 + vout R4   + R3ia    0 = -vin + R1 ia + gm ia R3 + vout R4     gm ia R3 + + R2  vout R4   + vout  vin = ia (R1 + R3 + gm R1 R2) + vout R1 R4 vin = ia (R1 + gm R1 R3 + gm R2 R3) + vout R1 + R2+ R4       R4 R1+R3 + gm R1 R3    R1+ R3 + gm R1 R3 R1+ gm R1 R3 + gm R2 R3 vin   vin  R1/ R4 R1+ gm R1 R3 + gm R2 R3 (R1+ R2+R4) / R4 vin R3 R4 (1 - gm R2)    2 2 (R1 + R3 + gm R1 R3) (R1 + R2 + R4) - (R 1 + gmR 1 R3 + gmR1 R2 R3) vout =    vout = vout = vout vin = vin R3 R4 (1 - gm R2) R1R2 + R1R4 + R1R3 + R2R3 + R3R4 + gm R1 R3 R4 R3 R4 (1 - gm R2) R1R2 + R1R4 + R1R3 + R2R3 + R3R4 + gm R1 R3 R4 1.1-6 Use the source rearrangement and substitution concepts to simplify the circuit shown in Fig. P1.6 and solve for iout/iin by making chain-type calculations only.
    CMOS Analog Circuit Design (2nd Ed.) Homework Solutions : 9/20/2002 5 i R2 iin R1 v1 rmi R3 iout i R2 iin R1 v1 rmi rmi R3 iout i R2 iin R1 v1 R-rm rmi R3 iout Figure P1.1-6 iout = -rm R3 i R1 i = R + R1 - rm iin iout iin = -rm R1/R3 R + R1 - rm 1.1-7 Find v2/v1 and v1/i1 of Fig. P1.7.
    CMOS Analog Circuit Design (2nd Ed.) Homework Solutions : 9/20/2002 6 gm(v1-v2) i1 v1 RL v2 Figure P1.1-7 v2 v1 = gm (v1 - v2) RL v2 (1 + gm RL ) = gm RL v1 v2 v1 = gm RL 1 + gm RL v2 = i1 RL substituting for v2 yields: i1 RL v1 = gm RL 1 + gm RL v1 i1 v1 i1 = RL( 1 + gm RL ) gm RL = RL + 1 gm 1.1-8 Use the circuit-reduction technique to solve for vout/vin of Fig. P1.8.
    CMOS Analog Circuit Design (2nd Ed.) Homework Solutions : 9/20/2002 7 Av(vin - v1) vin R1 v1 R2 vout N1 N2 Avv1 Avvin vin R1 v1 R2 vout Multiply R1 by (Av + 1) Figure P1.1-8a Avvin vin v1 R1(Av+1) R2 vout Figure P1.1-8b -Avvin R2 vout = R2 + R1(Av+1) vout vin = -Av R2 R2 + R1(Av+1)
    CMOS Analog Circuit Design (2nd Ed.) Homework Solutions : 9/20/2002 8 vout vin = -Av -Av + 1 R2 R2 Av + 1 + R1 As Av approaches infinity, vout vin = -R2 R1 1.1-9 Use the Miller simplification concept to solve for vout/vin of Fig. A-3 (see Appendix A). R1 vin R2 v1 ia R3 ib rmia vout Figure P1.1-9a (Figure A-3 Mesh analysis.) = -rm R2 K = = vout v1 -rm ia iaR2 Z1 = 1 + R3 rm R2 Z2 = -rm R2 - 1 R3 rm R2 -
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